Model 8 Population Based Practice Questions Answers Test With Solutions & More Shortcuts
PERCENTAGE PRACTICE TEST [11 - EXERCISES]
Model 1 Simple Percentage Questions
Model 2 Net Increase Or Decrease In %
Model 3 Reducing & Exceeding Prices
Model 4 X & Y Comparison
Model 5 Income & Expenditure
Model 6 Consumption & Remaining
Model 7 Marks Scored In Examinations
Model 8 Population Based
Model 9 Voters & Election
Model 10 Percentage With Allegations & Mixture
Model 11 Percentage With Ratios
Question : 21
Of the 1000 inhabitants in a town 60% are males of whom 20% are literate. If of all the inhabitants, 25% are literate, then what percentage of the females of the town are ilterate ?
a) 32.5
b) 27.5
c) 37.5
d) 22.5
Answer »Answer: (a)
Population of town = 1000
Males ⇒ 600; Females ⇒ 400
Literate males = ${600 × 20}/100$ = 120
Total literate inhabitants
= ${1000 × 25}/100$ = 250
Literate females = 250 – 120 = 130
Required percent = $130/400$ × 100 = 32.5%
Question : 22 [SSC CPO S.I.2003]
The value of a property depreciates every year by 10% of its value at the beginning of the year. The present value of the property is Rs.8100. What was its value 2 years ago ?
a) Rs.$(90/100)^2 × 8100$
b) Rs.10,000
c) Rs. $(100/110)^2 × 8100$
d) Rs.9801
Answer »Answer: (b)
Using Rule 18,
Suppose the value of property two years ago was Rs.x
According to question $x(1 - 10/100)^2 = 8100$
$x(90/100)^2 = 8100$
$x ={8100 × 10 × 10}/{9 × 9}$ = Rs.10000
Question : 23 [SSC CPO S.I.2003]
The population of a village has increased annually at the rate of 25%. If at the end of 3 years it is 10,000, the population in the beginning of the first year was
a) 5000
b) 5120
c) 4900
d) 4500
Answer »Answer: (b)
Using Rule 17,
Population in the beginning of the year
=$\text"Population after 3 years"/(1 + \text"Rate"/100)^{ \text"Time"}$
= $10000/(1 + 25/100)^3= 10000/(5/4)^3$
= ${10000 × 64}/125 = 5120$
Question : 24 [SSC CAPFs 2016]
The population of a town is 9000. It the number of females increases by 5% and the males by 7.5%, what will be the total population after increase. The number of females currently is 3000.
a) 9200
b) 9600
c) 10500
d) 9540
Answer »Answer: (b)
In the village,
Females = 3000; Males = 9000 – 3000 = 6000
After respective increases,
Population of village
= $3000 × 105/100 + {6000 × 107.5}/100$
= 3150 + 6450 = 9600
Question : 25
A TV was bought at a price of Rs.21,000. After one year the value of TV was depreciated by 5%. Find the value of the TV after one year.
a) Rs.20,950
b) Rs.19,950
c) Rs.18,950
d) Rs.17,950
Answer »Answer: (b)
Value of TV after one year = 21000 × (100 – 5)%
= ${21000 × 95}/100$ = Rs. 19950
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Model 8 Population Based Shortcuts »
Click to Read...Model 8 Population Based Online Quiz
Click to Start..PERCENTAGE SHORTCUTS AND TECHNIQUES WITH EXAMPLES
-
Model 1 Simple Percentage Questions
Defination & Shortcuts … -
Model 2 Net Increase Or Decrease In %
Defination & Shortcuts … -
Model 3 Reducing & Exceeding Prices
Defination & Shortcuts … -
Model 4 X & Y Comparison
Defination & Shortcuts … -
Model 5 Income & Expenditure
Defination & Shortcuts … -
Model 6 Consumption & Remaining
Defination & Shortcuts … -
Model 7 Marks Scored In Examinations
Defination & Shortcuts … -
Model 8 Population Based
Defination & Shortcuts … -
Model 9 Voters & Election
Defination & Shortcuts … -
Model 10 Percentage With Allegations & Mixture
Defination & Shortcuts … -
Model 11 Percentage With Ratios
Defination & Shortcuts …
QUANTITATIVE APTITUDE CATEGORIES
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» Number System
-
» Average
-
» LCM & HCF
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» Percentage
-
» Profit & Loss
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» Time & Work
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» Pipes & Cisterns
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» Time & Distance
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» Trains
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» Compound Interest
-
» Simplification
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» Discount
-
» Power
-
» Permutations & Combination
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» Ratio & Proportion
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» Advance Math
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» Algebraic Expressions
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» Trigonometric Ratios & Identities
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» Simple Interest
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» Alligation & Mixtures
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» Boats & Streams
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» Set Theory
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» Linear Equations
-
» Quadratic Equations
-
» Mensuration
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» Squareroots & Cuberoots
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» Data Sufficiency
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» Logarithm
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» Probability
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» Statistics
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